Question

Use the image to answer the question.

A circle has center point upper O. Upper O connects to a point on the circumference labeled upper B. Upper B connects to a point outside the circle labeled upper A. A diagonal line connects upper A and upper O to form the shape of a triangle.
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If BO=45
in. and BA=108
in., then what is the length of AO
to the nearest whole inch?

(1 point)

25 in.

117 in.

98 in.

67 in.

Answer 1

117 in.

Reason: BA is tangent to the circle at B, so OB ⟂ BA. Triangle OBA is right-angled at B, so OA = sqrt(OB^2 + BA^2) = sqrt(45^2 + 108^2) = sqrt(13689) = 117 in.