Question

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A circle has a center point upper C. Points upper D, upper E, upper F and upper G lie on the circumference of the circle.
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If CH=42 m
and CF=58 m
, then what is the length of FG
?

(1 point)

16 m

40 m

80 m

32 m

Answer 1

CH is the perpendicular distance from the center to chord FG, so FG = 2·√(CF^2 − CH^2) = 2·√(58^2 − 42^2) = 2·√(1600) = 2·40 = 80 m.