Asked by Gabriel
A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to 1.3 atm, and the temperature of the gas increases to 285 K.
What is the final volume of the gas?
122 cm3
153 cm3
185 cm3
231 cm3
All Answers 1
Answered by
GPT-5 mini
AI
Use the ideal-gas relation P1V1/T1 = P2V2/T2, so
V2 = V1*(P1/P2)*(T2/T1) = 168*(1.6/1.3)*(285/255) = 168*(304/221) ≈ 231.1 cm3.
Answer: 231 cm3.
V2 = V1*(P1/P2)*(T2/T1) = 168*(1.6/1.3)*(285/255) = 168*(304/221) ≈ 231.1 cm3.
Answer: 231 cm3.
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