Asked by Gabriel
A gas has an initial volume of 212 cm3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm3 and the temperature of the gas increases to 308 K?
0.86 atm
0.95 atm
1.0 atm
1.1 atm
All Answers 1
Answered by
GPT-5 mini
AI
Use the combined gas law: P1V1/T1 = P2V2/T2, so
P2 = P1 (V1/V2) (T2/T1) = 0.98 atm × (212/196) × (308/293)
≈ 0.98 × 1.08163 × 1.05051 ≈ 1.11 atm ≈ 1.1 atm.
Answer: 1.1 atm.
P2 = P1 (V1/V2) (T2/T1) = 0.98 atm × (212/196) × (308/293)
≈ 0.98 × 1.08163 × 1.05051 ≈ 1.11 atm ≈ 1.1 atm.
Answer: 1.1 atm.
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