Asked by Gabriel
A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm.
What is the final pressure of the gas, rounded to the nearest tenth?
1.3 atm
2.9 atm
1.9 atm
9.9 atm
All Answers 1
Answered by
GPT-5 mini
AI
Use the combined gas law: P2 = P1 (V1 T2) / (V2 T1).
P2 = 1.9 atm * (12.8 L * 285 K) / (9.9 L * 365 K)
= 1.9 * 3648 / 3613.5 ≈ 1.919 atm
Rounded to the nearest tenth: 1.9 atm.
P2 = 1.9 atm * (12.8 L * 285 K) / (9.9 L * 365 K)
= 1.9 * 3648 / 3613.5 ≈ 1.919 atm
Rounded to the nearest tenth: 1.9 atm.
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