Asked by ws
-1/2x to the power of 2-x+4=0 what is the solution and how do the solutions ti the equationin part a compare to the solution to x to the power of 2+2x-8=0
-1/2x to the power of 2-x+4=0 what is the solution and how do the solutions ti the equationin part a compare to the solution to x to the power of 2+2x-8=0
-1/2x to the power of 2-x+4=0 what is the solution and how do the solutions ti the equationin part a compare to the solution to x to the power of 2+2x-8=0
-1/2x to the power of 2-x+4=0 what is the solution and how do the solutions ti the equationin part a compare to the solution to x to the power of 2+2x-8=0
a the solutions are each multipled by 2
b the solutions are the same
c the solutioons are each divided by 2
the solutions are each shiffte 4 units left
All Answers 1
Answered by
GPT-5 mini
AI
Interpretation: I read the first equation as (-1/2)x^2 - x + 4 = 0.
Solve it:
(-1/2)x^2 - x + 4 = 0
Multiply both sides by -2: x^2 + 2x - 8 = 0
Factor: (x + 4)(x - 2) = 0
Solutions: x = -4 or x = 2.
Comparison: the second equation given is x^2 + 2x - 8 = 0, which is exactly the same equation we got after multiplying the first by -2. Multiplying an equation by a nonzero constant does not change its solutions, so the two equations have the same solutions.
Answer: x = -4, 2, and choice (b) "the solutions are the same."
If you meant a different original expression (for example ((-1/2)x)^2 - x + 4 = 0), tell me and I’ll redo it.
Solve it:
(-1/2)x^2 - x + 4 = 0
Multiply both sides by -2: x^2 + 2x - 8 = 0
Factor: (x + 4)(x - 2) = 0
Solutions: x = -4 or x = 2.
Comparison: the second equation given is x^2 + 2x - 8 = 0, which is exactly the same equation we got after multiplying the first by -2. Multiplying an equation by a nonzero constant does not change its solutions, so the two equations have the same solutions.
Answer: x = -4, 2, and choice (b) "the solutions are the same."
If you meant a different original expression (for example ((-1/2)x)^2 - x + 4 = 0), tell me and I’ll redo it.
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