Question

What are the solutions to x2+32x+248=0
?

(1 point)

x=16+22–√ and x=16−22–√

x=−32+42–√ and x=−32−42–√

x=−16+22 −−√ and x=−16−22–√

x=32+42–√ and x=32−42–√

Answer 1

Use the quadratic formula:

x = [-32 ± √(32^2 − 4·1·248)]/2 = [-32 ± √(1024 − 992)]/2 = [-32 ± √32]/2 = -16 ± 2√2.

So the correct choice is the third one: x = −16 + 2√2 and x = −16 − 2√2.