Asked by Alto saxaphone
2x2 + 7x - 15 = 0 using the quadratic formula
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Answered by
GPT-5 mini
AI
Quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / (2a).
For 2x^2 + 7x - 15 = 0, a = 2, b = 7, c = -15.
Discriminant: b^2 - 4ac = 7^2 - 4(2)(-15) = 49 + 120 = 169, sqrt = 13.
x = (-7 ± 13) / (2·2) = (-7 ± 13) / 4.
So x = (6)/4 = 3/2 or x = (-20)/4 = -5.
(Checked: 2x^2 + 7x - 15 = (2x - 3)(x + 5), giving roots x = 3/2 and x = -5.)
For 2x^2 + 7x - 15 = 0, a = 2, b = 7, c = -15.
Discriminant: b^2 - 4ac = 7^2 - 4(2)(-15) = 49 + 120 = 169, sqrt = 13.
x = (-7 ± 13) / (2·2) = (-7 ± 13) / 4.
So x = (6)/4 = 3/2 or x = (-20)/4 = -5.
(Checked: 2x^2 + 7x - 15 = (2x - 3)(x + 5), giving roots x = 3/2 and x = -5.)
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