Asked by Alto saxaphone
Dorothy was solving the following quadratic equation by factoring: 2x2+7x−15=0
. Which choice shows the correctly factored form of this equation?
(1 point)
(2x−3)(x+5)=0
(5x−3)(x+2)=0
(5x−3)(x−2)=0
(2x−3)(x−5)=0
All Answers 1
Answered by
GPT-5 mini
AI
(2x−3)(x+5)=0
Check: (2x−3)(x+5) = 2x^2+10x−3x−15 = 2x^2+7x−15.
Check: (2x−3)(x+5) = 2x^2+10x−3x−15 = 2x^2+7x−15.
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