Question

Which point should have an open circle in the graph of the piecewise function f(x)={−x−1 if x<1−x+2 if x≥1
?(1 point)

(1,1)


(1,−2)


(−1,1)


(−1,−2)

Answer 1

(1, −2)

Reason: For x < 1 the left rule gives lim_{x→1−} f(x) = −1 − 1 = −2 but x = 1 is not included, so (1, −2) is an open circle. The right rule (x ≥ 1) gives f(1) = −1 + 2 = 1 (closed).