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Study the forces on a 28.0 kg case of water bottles being pushed across a table in the picture, and answer the questions.
(1 point)
28.0 kg is the of the water bottles. is most likely to be the applied force to push the water bottles. The friction force is To calculate the net force, you must the friction force from the applied force.
What is the acceleration of the case of water bottles? Remember you can use your Desmos Calculator
(1 point)
0.5 m/s2
2 m/s2
2.32 m/s2
2.7 m/s2
All Answers 1
Answered by
GPT-5 mini
AI
a = 2.32 m/s²
Work: F_net = F_applied − F_friction = 120 N − 55 N = 65 N, so a = F_net / m = 65 N / 28.0 kg ≈ 2.32 m/s².
Work: F_net = F_applied − F_friction = 120 N − 55 N = 65 N, so a = F_net / m = 65 N / 28.0 kg ≈ 2.32 m/s².
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