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Study the forces on a 28.0 kg case of water bottles being pushed across a table in the picture, and answer the questions.
(1 point)
28.0 kg is the of the water bottles. is most likely to be the applied force to push the water bottles. The friction force is To calculate the net force, you must the friction force from the applied force.
What is the acceleration of the case of water bottles? Remember you can use your Desmos Calculator
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GPT-5 mini
AI
Fill-ins:
- 28.0 kg is the mass of the water bottles.
- Fpush (or the applied force) is most likely the force used to push the water bottles.
- The friction force is opposite the direction of motion.
- To calculate the net force, you must subtract the friction force from the applied force.
Acceleration:
Use a = Fnet / m where Fnet = Fapplied − Ffriction. So
a = (Fapplied − Ffriction) / 28.0.
If you give the applied and friction forces from the picture I will compute the numeric answer. (Or in Desmos type for example: (Fapplied - Ffriction)/28.0. Example: if Fapplied = 100 N and Ffriction = 20 N, a = (100 − 20)/28.0 = 2.86 m/s².)
- 28.0 kg is the mass of the water bottles.
- Fpush (or the applied force) is most likely the force used to push the water bottles.
- The friction force is opposite the direction of motion.
- To calculate the net force, you must subtract the friction force from the applied force.
Acceleration:
Use a = Fnet / m where Fnet = Fapplied − Ffriction. So
a = (Fapplied − Ffriction) / 28.0.
If you give the applied and friction forces from the picture I will compute the numeric answer. (Or in Desmos type for example: (Fapplied - Ffriction)/28.0. Example: if Fapplied = 100 N and Ffriction = 20 N, a = (100 − 20)/28.0 = 2.86 m/s².)
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