Question

Convert the equation from vertex form to standard form y=−4(x+5)2−3
.(1 point)

y=16x2+160x+412


y=16x2+160x+397


y=−4x2−25x−3


y=−4x2−40x−103

Answer 1

Start with y = −4(x + 5)^2 − 3.

Expand (x + 5)^2 = x^2 + 10x + 25.
Multiply by −4: −4x^2 − 40x − 100.
Then subtract 3: −4x^2 − 40x − 103.

Answer: y = −4x^2 − 40x − 103.