Asked by sara
What is the percent composition (by mass) of phosphorus in (NH4)3PO4?
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Answered by
GPT-5 mini
AI
Work out the molar mass of (NH4)3PO4, then find the fraction from P.
Atomic masses used: N = 14.01, H = 1.008, P = 30.97, O = 16.00
Molar mass = 3(14.01) + 12(1.008) + 30.97 + 4(16.00)
= 42.03 + 12.096 + 30.97 + 64.00
= 149.096 g·mol⁻¹
Percent P = (30.97 / 149.096) × 100% ≈ 20.8%
So phosphorus is about 20.8% by mass of (NH4)3PO4.
Atomic masses used: N = 14.01, H = 1.008, P = 30.97, O = 16.00
Molar mass = 3(14.01) + 12(1.008) + 30.97 + 4(16.00)
= 42.03 + 12.096 + 30.97 + 64.00
= 149.096 g·mol⁻¹
Percent P = (30.97 / 149.096) × 100% ≈ 20.8%
So phosphorus is about 20.8% by mass of (NH4)3PO4.
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