Question

What are the coordinates of the minimum point for the square root function that relates to the quadratic function f(x)=12(x−11)2+4?

(1 point)

(-11, 4)

(11, 4)

(4, 11)

(-11, -4)

Answer 1

(11, 4)

The quadratic is in vertex form f(x) = 12(x − 11)^2 + 4, so the vertex (minimum) is at x = 11 with f(11) = 4.