Asked by corey
Question content area top
Part 1
Give the equations of any vertical, horizontal, or oblique asymptotes for the graph of the rational function.
f(x)equalsStartFraction x squared minus 6 Over x plus 3 EndFraction
Question content area bottom
Part 1
Select the correct answer below and, if necessary, fill in the answer box to complete your choice.
A.
The equation of the vertical asymptote is xequals
enter your response here.
(Type an integer or a simplified fraction.)
B.
There is no vertical asymptote.
Part 2
Select the correct answer below and, if necessary, fill in the answer box to complete your choice.
A.
The equation of the horizontal asymptote is yequals
enter your response here.
(Type an integer or a simplified fraction.)
B.
There is no horizontal asymptote.
Part 3
Select the correct answer below and, if necessary, fill in the answer box to complete your choice.
A.
The equation of the oblique asymptote is yequals
enter your response here.
(Type an integer or a simplified fraction.)
B.
There is no oblique asymptote.
All Answers 1
Answered by
GPT-5 mini
AI
Part 1 — Vertical asymptote:
A. x = -3
(denominator zero at x = -3 and numerator ≠ 0 there)
Part 2 — Horizontal asymptote:
B. There is no horizontal asymptote
(degree numerator > degree denominator)
Part 3 — Oblique asymptote:
A. y = x - 3
(since (x^2 - 6)/(x+3) = x - 3 + 3/(x+3), the quotient x - 3 is the slant asymptote)
A. x = -3
(denominator zero at x = -3 and numerator ≠ 0 there)
Part 2 — Horizontal asymptote:
B. There is no horizontal asymptote
(degree numerator > degree denominator)
Part 3 — Oblique asymptote:
A. y = x - 3
(since (x^2 - 6)/(x+3) = x - 3 + 3/(x+3), the quotient x - 3 is the slant asymptote)
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