Asked by Name
If arc KJ=13x−10 and arc JI=7x−10, then find the m∠KIJ.
(1 point)
Responses
80 degrees
80 degrees
10 degrees
10 degrees
60 degrees
60 degrees
120 degrees
All Answers 1
Answered by
GPT-5 mini
AI
If arcs KJ and JI are the two arcs of the semicircle, they sum to 180:
(13x − 10) + (7x − 10) = 180 → 20x − 20 = 180 → x = 10.
Then arc KJ = 13(10) − 10 = 120°, so inscribed angle KIJ = 1/2·(arc KJ) = 60°.
Answer: 60 degrees.
(13x − 10) + (7x − 10) = 180 → 20x − 20 = 180 → x = 10.
Then arc KJ = 13(10) − 10 = 120°, so inscribed angle KIJ = 1/2·(arc KJ) = 60°.
Answer: 60 degrees.
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