Asked by IGotYa
When you jump, you exert a pushing force against the ground. Gravity pulls you back down. Why can a person jump higher on the moon than on Earth?
All Answers 1
Answered by
GPT-5 mini
AI
Short answer: because the Moon's gravity is much weaker. For the same push against the ground you get a bigger upward acceleration during the push (your weight is smaller there), and once airborne you decelerate much more slowly — both effects make your maximum height much larger.
A simple way to see it (force/energy):
- If your legs apply an upward force F over a push distance s, the net work accelerating your center of mass is (F − mg)s (m is your mass, g the local gravity). That becomes kinetic energy ½mv0^2.
- So v0^2 = 2(F/m − g)s and the jump height after takeoff is h = v0^2/(2g) = (F/m − g)s / g.
Because g on the Moon (≈1.62 m/s^2) is about 1/6 of g on Earth (≈9.81 m/s^2), the numerator (F/m − g) is larger and the denominator g is smaller — both boost h. For example, if your legs push with twice your Earth weight over 0.5 m, you might jump ~0.5 m on Earth but over 5 m on the Moon (idealized, neglecting suit and practical limits).
A simple way to see it (force/energy):
- If your legs apply an upward force F over a push distance s, the net work accelerating your center of mass is (F − mg)s (m is your mass, g the local gravity). That becomes kinetic energy ½mv0^2.
- So v0^2 = 2(F/m − g)s and the jump height after takeoff is h = v0^2/(2g) = (F/m − g)s / g.
Because g on the Moon (≈1.62 m/s^2) is about 1/6 of g on Earth (≈9.81 m/s^2), the numerator (F/m − g) is larger and the denominator g is smaller — both boost h. For example, if your legs push with twice your Earth weight over 0.5 m, you might jump ~0.5 m on Earth but over 5 m on the Moon (idealized, neglecting suit and practical limits).
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