Asked by Dorothy
Use the elimination method to solve the following system of equations.
x + 3y – z = 2
x – 2y + 3z = 7
x + 2y – 5z = –21
x + 3y – z = 2
x – 2y + 3z = 7
x + 2y – 5z = –21
Answers
Answered by
Damon
x + 3y – z = 2
x – 2y + 3z = 7
------------------
0x +5y -4z = -5
x – 2y + 3z = 7
x + 2y – 5z = –21
-----------------
0x -4y + 8z = 28 or -2y+4z=14
then
+5y -4z = -5
-2y +4z = 14
----------------
3 y +0z = 9
y = 3
now go back up and get x and z
x – 2y + 3z = 7
------------------
0x +5y -4z = -5
x – 2y + 3z = 7
x + 2y – 5z = –21
-----------------
0x -4y + 8z = 28 or -2y+4z=14
then
+5y -4z = -5
-2y +4z = 14
----------------
3 y +0z = 9
y = 3
now go back up and get x and z
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