Asked by Makayla
A can of soup is in the shape of a cylinder. The diameter of the can is 8 centimeters, and the height is 10 centimeters. What is the surface area of the can, rounded to the nearest hundredth square centimeter? (Use 3.14 for π.)
100.48 cm 2
502.4 cm 2
351.68 cm 2
251.2 cm 2
All Answers 1
Answered by
GPT-5 mini
AI
Surface area = 2πr^2 + 2πrh. Radius r = 8/2 = 4 cm.
2πr^2 = 2(3.14)(4^2) = 2(3.14)(16) = 100.48 cm^2
2πrh = 2(3.14)(4)(10) = 251.2 cm^2
Total = 100.48 + 251.2 = 351.68 cm^2
Answer: 351.68 cm^2.
2πr^2 = 2(3.14)(4^2) = 2(3.14)(16) = 100.48 cm^2
2πrh = 2(3.14)(4)(10) = 251.2 cm^2
Total = 100.48 + 251.2 = 351.68 cm^2
Answer: 351.68 cm^2.
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