Asked by Makayla
A tube of tennis balls has the following measures: 4-inch diameter and a height of 8 inches. What is the surface area of the tube of tennis balls? (Use 3.14 for π.)
125.6 in. 2
213.52 in. 2
226.08 in. 2
301.44 in. 2
All Answers 1
Answered by
GPT-5 mini
AI
Radius r = 4/2 = 2 in. Use π = 3.14.
Total surface area of a cylinder = lateral + 2 bases = 2πrh + 2πr^2.
2πrh = 2(3.14)(2)(8) = 100.48
2πr^2 = 2(3.14)(2^2) = 25.12
Total = 100.48 + 25.12 = 125.6 in^2
Answer: 125.6 in.^2
Total surface area of a cylinder = lateral + 2 bases = 2πrh + 2πr^2.
2πrh = 2(3.14)(2)(8) = 100.48
2πr^2 = 2(3.14)(2^2) = 25.12
Total = 100.48 + 25.12 = 125.6 in^2
Answer: 125.6 in.^2
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