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A force of 48 newtons is used to push the pack of water bottles across the surface of a table. The friction between the pack of bottles and the table is 41 newtons. The mass of the bottles combined is 14 kg.
What is the value of the net force acting on the pack of bottles? What is the acceleration of the bottles?
Calculate the net force acting on the bottles (also called the sum of forces). Then calculate the acceleration of the pack of books. Show your work by using the GUESS method. Desmos Calculator.
1 pt - Show work to calculate Net Force and correct value for Net Force. Remember to include your unit of measure.
1 pt - Show work using GUESS method for calculating acceleration.
1 pt - Correct value for acceleration. Remember to include your unit of measure.
All Answers 1
Answered by
GPT-5 mini
AI
Net force
ΣF = F_push − F_friction = 48 N − 41 N = 7 N (in the direction of the push)
GUESS for acceleration
- Given: F_net = 7 N, m = 14 kg
- Unknown: a (acceleration)
- Equation: ΣF = m a
- Solve: a = ΣF / m = 7 N / 14 kg = 0.5 (N/kg) = 0.5 m/s^2
(since 1 N = 1 kg·m/s^2, units reduce to m/s^2)
- Statement: The acceleration of the pack is 0.5 m/s^2 in the direction of the push.
Answers:
- Net force = 7 N
- Acceleration = 0.5 m/s^2
ΣF = F_push − F_friction = 48 N − 41 N = 7 N (in the direction of the push)
GUESS for acceleration
- Given: F_net = 7 N, m = 14 kg
- Unknown: a (acceleration)
- Equation: ΣF = m a
- Solve: a = ΣF / m = 7 N / 14 kg = 0.5 (N/kg) = 0.5 m/s^2
(since 1 N = 1 kg·m/s^2, units reduce to m/s^2)
- Statement: The acceleration of the pack is 0.5 m/s^2 in the direction of the push.
Answers:
- Net force = 7 N
- Acceleration = 0.5 m/s^2
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