Question

Nala can spend no more than $150 per month on gasoline. She has already purchased $60 in gas this month. Which inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30?

30n + 60 > 150
30n + 60 < 150
60n + 30 < 150
60n + 30 > 150

Answer 1

Let n = number of additional fill-ups. Total spent is 60 + 30n and must be at most 150, so 30n + 60 ≤ 150. From the choices given the closest is

30n + 60 < 150.

Solving gives 30n ≤ 90, so n ≤ 3 — she can buy at most 3 more fill-ups.