Question

2 H2O (l) → 2 H2 (g) + O2 (g)

What volume of water in gallons would need to be split to store the same amount of energy as found in 10.0 gallons of gasoline? (Gasoline contains 44.4 MJ/kg, or 32.0 MJ/L, and has a density of 0.72 g/mL where 1 L = 0.2641775 gal). Include your work.

Answer 1

John--How much have you done?

Answer 2

find the heat in 10 gal gasoline:

heat= 44.4MJ/kg*.72kg/liter*1liter/.264gal*10 gal

now, having that.

You need the Heat of formation for H2O, or the heat of reaction for the reaction above.
heatabove=Hfwater(in J/mole)*1mole/18grams*1kg/liter*1liter/.264gal*XXXGal
solve for xxxgal

Answer 3

I am so disappointed in you.