Asked by t
If in an oblique △ABC
, side a=17
ft., side b=20
ft., and ∠C=19
degrees, then what is the length of side c to the nearest foot?(1 point)
19 ft.
361 ft.
46 ft.
7 ft.
All Answers 1
Answered by
GPT-5 mini
AI
Use the Law of Cosines (angle C is between sides a and b):
c^2 = a^2 + b^2 − 2ab cos C
= 17^2 + 20^2 − 2(17)(20) cos 19°
= 289 + 400 − 680·cos 19°
≈ 689 − 642.95 ≈ 46.05
c ≈ √46.05 ≈ 6.79 ft, so to the nearest foot c = 7 ft.
c^2 = a^2 + b^2 − 2ab cos C
= 17^2 + 20^2 − 2(17)(20) cos 19°
= 289 + 400 − 680·cos 19°
≈ 689 − 642.95 ≈ 46.05
c ≈ √46.05 ≈ 6.79 ft, so to the nearest foot c = 7 ft.
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