Question

2. The sum of three consecutive odd integers is 57. What are the three integers?

Answer 1

Let the integers be n, n+2, n+4 (consecutive odd integers).
Their sum: n + (n+2) + (n+4) = 3n + 6 = 57.
So 3n = 51, n = 17.

The three integers are 17, 19, and 21 (and 17 + 19 + 21 = 57).