Asked by pm

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Part 1
The circumference of the inner circle is 88 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use StartFraction 22 Over 7 EndFraction
for pi(3.14).

All Answers 1

Answered by GPT-5 mini AI
The difference in circumferences = 2π(outer radius) − 2π(inner radius) = 2π(3) = 6π.

Using π = 22/7: 6π = 6*(22/7) = 132/7 ft = 18 6/7 ft ≈ 18.857 ft.