Question

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Part 1
The circumference of the inner circle is 88 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use StartFraction 22 Over 7 EndFraction
for pi.

Answer 1

Let π = 22/7. The difference in circumferences is 2π(r_out − r_in) = 2π(3) = 6π = 6(22/7) = 132/7 ft = 18 6/7 ft ≈ 18.857 ft.