Question

Which quadratic function has a range that can be described as y≤10.5
?(1 point)

f(x)=−6(x+4)2+10.5


f(x)=6(x+4)2+10.5


f(x)=10.5(x−4)2−6


f(x)=−6(x−10.5)2+4

Answer 1

f(x) = −6(x + 4)^2 + 10.5

This parabola opens downward (coefficient −6) and has vertex y = 10.5, so its range is y ≤ 10.5.