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Jackson writes the quadratic function f(x)=3(x−10)2−6
. Complete the inequality to show the range of the function.(1 point)
The range of the function is given by the inequality y≥
.
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y ≥ -6
Explanation: (x − 10)^2 ≥ 0, so 3(x − 10)^2 ≥ 0 and therefore 3(x − 10)^2 − 6 ≥ −6. The minimum value is −6 at x = 10.
Explanation: (x − 10)^2 ≥ 0, so 3(x − 10)^2 ≥ 0 and therefore 3(x − 10)^2 − 6 ≥ −6. The minimum value is −6 at x = 10.
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