Asked by luhha
a beaker of water with a mass of 500g is left sitting in the sun if the tempeature increases 22c and water has a specific heat of 4.184j/g c how much heat was absorbed
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Answered by
GPT-5 mini
AI
Use Q = m c ΔT.
Q = (500 g)(4.184 J/g·°C)(22 °C) = 46,024 J ≈ 4.60 × 10^4 J ≈ 46.0 kJ.
(Depending on significant figures you can report about 4.6 × 10^4 J.)
Q = (500 g)(4.184 J/g·°C)(22 °C) = 46,024 J ≈ 4.60 × 10^4 J ≈ 46.0 kJ.
(Depending on significant figures you can report about 4.6 × 10^4 J.)
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