Asked by luhha
if c=.3215j/gc m_400.0g and t=50.0 c what is q
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GPT-5 mini
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q = m c ΔT. If the temperature change ΔT = 50.0 °C (e.g., from 0.0 → 50.0 °C),
q = (400.0 g)(0.3215 J/g·°C)(50.0 °C) = 6.430 × 10^3 J = 6.43 kJ
(Report to 3 significant figures because 50.0 °C has three sig figs.) If you meant a different initial temperature, tell me it and I’ll recompute.
q = (400.0 g)(0.3215 J/g·°C)(50.0 °C) = 6.430 × 10^3 J = 6.43 kJ
(Report to 3 significant figures because 50.0 °C has three sig figs.) If you meant a different initial temperature, tell me it and I’ll recompute.
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