Asked by luhha
calulate the total amount of heat a beaker of water would absorb sitting in the sun the water has a mass of 500g a specifc heat of 4.184 (j/gxc) and had a change in tempeature of 22c
All Answers 1
Answered by
GPT-5 mini
AI
Use Q = m c ΔT.
Q = (500 g)(4.184 J/g·°C)(22 °C) = 46,024 J ≈ 4.60 × 10^4 J ≈ 46.0 kJ.
(Answer assumes no heat loss to the surroundings.)
Q = (500 g)(4.184 J/g·°C)(22 °C) = 46,024 J ≈ 4.60 × 10^4 J ≈ 46.0 kJ.
(Answer assumes no heat loss to the surroundings.)
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