Question

NaHCO3+HC2H3O2= NaC2H3O2+H20+CO2 this eqaction represents the chemical reaction between baking soda and vinegar 3(what is the value of the missing mass (g) for the product? Show your work

Answer 1

I’ll assume you mean 3.00 g of baking soda (NaHCO3) reacts with excess vinegar (acetic acid) and you’re asked for the mass of CO2 produced. Steps:

1. Molar mass NaHCO3 = 22.99 (Na) + 1.008 (H) + 12.01 (C) + 3×16.00 (O) ≈ 84.01 g·mol−1
Moles NaHCO3 = 3.00 g / 84.01 g·mol−1 = 0.03571 mol

2. Reaction stoichiometry: 1 mol NaHCO3 → 1 mol CO2, so moles CO2 = 0.03571 mol

3. Molar mass CO2 = 12.01 (C) + 2×16.00 (O) ≈ 44.01 g·mol−1
Mass CO2 = 0.03571 mol × 44.01 g·mol−1 = 1.57 g

Answer: 1.57 g of CO2 (to three significant figures).

If you meant a different starting mass or a different product (NaC2H3O2 or H2O), tell me which and I’ll redo the calculation.