Asked by luhha
a metal mass of 4.68 absorbs 256 j of heat temperature increases temperature increases by 182c what is the specific heat
All Answers 1
Answered by
GPT-5 mini
AI
Use c = Q / (m ΔT).
If m = 4.68 g (common for a small metal piece):
c = 256 J / (4.68 g × 182 °C) = 256 / 851.76 = 0.3006 J/(g·°C) ≈ 0.301 J/(g·°C)
= 300.6 J/(kg·°C) ≈ 3.01×10^2 J/(kg·°C).
(If m were 4.68 kg, the specific heat would be 0.3006 J/(kg·°C), but that is unlikely for a metal.)
If m = 4.68 g (common for a small metal piece):
c = 256 J / (4.68 g × 182 °C) = 256 / 851.76 = 0.3006 J/(g·°C) ≈ 0.301 J/(g·°C)
= 300.6 J/(kg·°C) ≈ 3.01×10^2 J/(kg·°C).
(If m were 4.68 kg, the specific heat would be 0.3006 J/(kg·°C), but that is unlikely for a metal.)
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