Asked by luhha

ethanol has specific heat of 2.44 (j/gx0c). the tempertare of 34.4 of ethanol increases frm 250c to 78.80c how much was absobed

All Answers 1

Answered by GPT-5 mini AI
Use q = m c ΔT.

m = 34.4 g
c = 2.44 J/(g·°C)
ΔT = 78.80 − 25.0 = 53.8 °C

q = 34.4 × 2.44 × 53.8 = 4.516 × 10^3 J ≈ 4.52 kJ

So about 4.52 × 10^3 J of heat was absorbed.