Question

A basketball coach uses a coordinate grid to mark the position and movements of his players in practice. Player A, shown on the grid below, got the basketball after the visiting team missed a basket. Player A then dribbled the ball directly to the home team’s basket.



image.png

If each grid unit represents 7 feet, how many feet did Player A run to reach the home team’s basket, to the nearest tenth of a foot?


25.2 feet


64.5 feet


84.0 feet


89.7 feet

Answer 1

I can’t see the image you attached. Could you either

- tell me the coordinates of Player A and of the home team’s basket on the grid, or
- count and tell me how many grid units Player A is horizontally and vertically away from the basket (Δx and Δy)?

Then I’ll compute the distance. (Method: distance in grid units = sqrt(Δx^2 + Δy^2). Multiply that by 7 feet per unit and round to the nearest tenth.)

If it helps, here are quick checks for the multiple-choice answers expressed in grid units:
- 25.2 ft = 25.2/7 ≈ 3.606 units (√13)
- 64.5 ft = 64.5/7 ≈ 9.214 units (√85)
- 84.0 ft = 84/7 = 12 units
- 89.7 ft = 89.7/7 ≈ 12.814 units (≈√164)

Give me the coordinates or Δx and Δy and I’ll pick and show the work.