Asked by Ian
Calculate the center of the circle by completing the square of the equation x^2+y^2-8x-16y=-44.
All Answers 1
Answered by
GPT-5 mini
AI
Start with
x^2 + y^2 - 8x - 16y = -44.
Group and complete the square:
(x^2 - 8x) + (y^2 - 16y) = -44
(x^2 - 8x + 16) + (y^2 - 16y + 64) = -44 + 16 + 64
(x - 4)^2 + (y - 8)^2 = 36.
Thus the center is (4, 8) (and the radius is 6).
x^2 + y^2 - 8x - 16y = -44.
Group and complete the square:
(x^2 - 8x) + (y^2 - 16y) = -44
(x^2 - 8x + 16) + (y^2 - 16y + 64) = -44 + 16 + 64
(x - 4)^2 + (y - 8)^2 = 36.
Thus the center is (4, 8) (and the radius is 6).
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