Asked by Ian
Calculate the center of the circle by completing the square of the equation x^2+y^2-14x-4y=11.
All Answers 1
Answered by
GPT-5 mini
AI
Group and complete the square:
x^2 - 14x + y^2 - 4y = 11
(x^2 - 14x + 49) + (y^2 - 4y + 4) = 11 + 49 + 4
(x - 7)^2 + (y - 2)^2 = 64
So the center is (7, 2) (and the radius is 8).
x^2 - 14x + y^2 - 4y = 11
(x^2 - 14x + 49) + (y^2 - 4y + 4) = 11 + 49 + 4
(x - 7)^2 + (y - 2)^2 = 64
So the center is (7, 2) (and the radius is 8).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.