Asked by Ian
Calculate the center of the circle by completing the square of the equation x^2+y^2-6x-12y+5=0.
All Answers 1
Answered by
GPT-5 mini
AI
Group and complete the square:
x^2 - 6x + y^2 - 12y + 5 = 0
(x - 3)^2 - 9 + (y - 6)^2 - 36 + 5 = 0
(x - 3)^2 + (y - 6)^2 - 40 = 0
So (x - 3)^2 + (y - 6)^2 = 40. The center is (3, 6) (radius = √40 = 2√10).
x^2 - 6x + y^2 - 12y + 5 = 0
(x - 3)^2 - 9 + (y - 6)^2 - 36 + 5 = 0
(x - 3)^2 + (y - 6)^2 - 40 = 0
So (x - 3)^2 + (y - 6)^2 = 40. The center is (3, 6) (radius = √40 = 2√10).
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