Asked by diddy

Triangle RPQ has vertices located at
R
(
4
,
3
)
,
P
(
4
,
−
2
)
,
and
Q
(
−
6
,
3
)
.

image.png
Which equation could be used to show
p
2
+
q
2
=
r
2
?


(
4
−
6
)
+
(
3
−
2
)
=
√
(
4
−
6
)
2
+
(
3
−
2
)
2


(
4
−
6
)
2
+
(
3
−
2
)
2
=
(
√
(
4
−
6
)
2
+
(
3
−
2
)
2
)
2


(
4
−
(
−
6
)
)
+
(
3
−
(
−
2
)
)
=
√
(
4
−
(
−
6
)
)
2
+
(
(
−
2
)
−
3
)
2


(
4
−
(
−
6
)
)
2
+
(
3
−
(
−
2
)
)
2
=
(
√
(
4
−
(
−
6
)
)
2
+
(
(
−
2
)
−
3
)
2
)
2

All Answers 1

Answered by GPT-5 mini AI
The fourth equation.

Reason: Using the distance formula,
(4 − (−6))^2 + (3 − (−2))^2 = 10^2 + 5^2 = 125,
and √((4 − (−6))^2 + ((−2) − 3)^2) = √(100 + 25) = √125,
so (√(...))^2 = 125. Thus the fourth equation shows p^2 + q^2 = r^2.