Asked by huhhf3;q
1. What happens to the kinetic and potential energy as two electrons move closer to one another? A:
2. Is the force between an electron and a proton as they come closer together attractive or repulsive? A:
3. When two bar magnets are placed end-to-end they repel each other. What does that tell us about their charges? A:
4. What is Coulomb's law? A:
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1. Two electrons have like charges, so as they are brought closer their electrostatic potential energy increases (it becomes more positive). To move them closer you must do work against the repulsive force; that work goes into increasing potential energy and (unless the work is supplied by slowing them) the electrons’ kinetic energy will decrease. If instead they were free and released from rest at some separation, they would accelerate apart, converting potential energy into kinetic.
2. The force between an electron and a proton is attractive (opposite charges attract).
3. Nothing about electric charge — bar magnets are magnetized objects with north and south poles. If two magnets placed end-to-end repel, like magnetic poles are facing each other (e.g., north–north or south–south). Magnets remain electrically neutral overall; the observation is about magnetic poles, not electric charge.
4. Coulomb’s law: the magnitude of the electrostatic force between two point charges q1 and q2 separated by distance r is
F = k |q1 q2| / r^2,
where k = 1/(4πε0) ≈ 8.99×10^9 N·m^2/C^2. The force acts along the line joining the charges, is repulsive for like charges and attractive for opposite charges. (Vector form: F12 = (1/(4πε0))·(q1 q2 / r^2) r̂12.)
2. The force between an electron and a proton is attractive (opposite charges attract).
3. Nothing about electric charge — bar magnets are magnetized objects with north and south poles. If two magnets placed end-to-end repel, like magnetic poles are facing each other (e.g., north–north or south–south). Magnets remain electrically neutral overall; the observation is about magnetic poles, not electric charge.
4. Coulomb’s law: the magnitude of the electrostatic force between two point charges q1 and q2 separated by distance r is
F = k |q1 q2| / r^2,
where k = 1/(4πε0) ≈ 8.99×10^9 N·m^2/C^2. The force acts along the line joining the charges, is repulsive for like charges and attractive for opposite charges. (Vector form: F12 = (1/(4πε0))·(q1 q2 / r^2) r̂12.)
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