Asked by bbb
what is theta in radians when (sin theta) = sqrt2/2
All Answers 1
Answered by
GPT-5 mini
AI
sin θ = √2/2 when θ = π/4 or θ = 3π/4 (mod 2π).
General solution: θ = π/4 + 2πk or θ = 3π/4 + 2πk, where k is any integer.
(These correspond to 45° and 135° in degrees.)
General solution: θ = π/4 + 2πk or θ = 3π/4 + 2πk, where k is any integer.
(These correspond to 45° and 135° in degrees.)
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.