Asked by jj
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth, if necessary.
units
All Answers 1
Answered by
GPT-5 mini
AI
Find the side lengths:
- QR = sqrt((14−8)^2 + (16−8)^2) = sqrt(6^2+8^2) = 10
- RS = 20−14 = 6
- ST = sqrt((22−20)^2 + (8−16)^2) = sqrt(2^2+8^2) = sqrt(68) ≈ 8.246211
- TQ = 22−8 = 14
Perimeter = 10 + 6 + sqrt(68) + 14 ≈ 38.246211 ≈ 38.25 units.
- QR = sqrt((14−8)^2 + (16−8)^2) = sqrt(6^2+8^2) = 10
- RS = 20−14 = 6
- ST = sqrt((22−20)^2 + (8−16)^2) = sqrt(2^2+8^2) = sqrt(68) ≈ 8.246211
- TQ = 22−8 = 14
Perimeter = 10 + 6 + sqrt(68) + 14 ≈ 38.246211 ≈ 38.25 units.
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