Question

On a coordinate plane, trapezoid A B C D has points (16, 1), (5, 3), (1, 6), and (0, 13). An altitude is drawn from point C to point E at (4, 10).
The height, CE, of the trapezoid is 5 units. What is the area of the trapezoid?

AD =
units

BC =
units

The area of the trapezoid is
square units.

Answer 1

AD = distance between (16,1) and (0,13) = sqrt(16^2 + (-12)^2) = sqrt(400) = 20 units

BC = distance between (5,3) and (1,6) = sqrt(4^2 + (-3)^2) = sqrt(25) = 5 units

Height CE = 5 units, so area = (1/2)(AD + BC) * height = (1/2)(20 + 5) * 5 = (25/2)*5 = 125/2 = 62.5 square units