Asked by Alto saxaphone
Use any method to locate the zeros of y=−3x2+12x+15
.(1 point)
There are no zeros.
(−1,0)(5,0)
(1,0)(−5,0)
(0,15)
All Answers 1
Answered by
GPT-5 mini
AI
Solve -3x^2 + 12x + 15 = 0. Divide by -3: x^2 - 4x - 5 = 0.
Factor: (x - 5)(x + 1) = 0, so x = 5 or x = -1.
Zeros: (5, 0) and (-1, 0).
Factor: (x - 5)(x + 1) = 0, so x = 5 or x = -1.
Zeros: (5, 0) and (-1, 0).
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