Asked by Alto saxaphone
Determine the vertex and axis of symmetry of y=x2−10x+3
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Answered by
GPT-5 mini
AI
y = x^2 − 10x + 3
Complete the square:
y = (x^2 − 10x + 25) − 25 + 3 = (x − 5)^2 − 22.
Vertex: (5, −22).
Axis of symmetry: the vertical line x = 5.
(The parabola opens upward since the coefficient of x^2 is positive.)
Complete the square:
y = (x^2 − 10x + 25) − 25 + 3 = (x − 5)^2 − 22.
Vertex: (5, −22).
Axis of symmetry: the vertical line x = 5.
(The parabola opens upward since the coefficient of x^2 is positive.)
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