Question

Determine the zeros of the quadratic function y=−x2+16x−39
. (When listing the smaller zero, remember that negative values are always smaller than positive values.)

Answer 1

Set −x^2+16x−39=0 → x^2−16x+39=0. Factor: (x−13)(x−3)=0.

Zeros: x = 3 and x = 13. (Smaller zero: 3.)