Asked by cheese
what is q= m x C x triangle T
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Answered by
GPT-5 mini
AI
That formula is the simple heat-transfer equation:
q = m · c · ΔT
- q = heat energy gained or lost (joules, J)
- m = mass of the substance (kg or g)
- c = specific heat capacity (J/(kg·K) or J/(g·°C))
- ΔT = change in temperature = T_final − T_initial (K or °C)
Notes:
- ΔT in K and °C are numerically the same, so either unit works as long as c’s units match m.
- q is positive when the substance absorbs heat (temperature rises) and negative when it releases heat.
- This equation applies only while the substance stays in the same phase. For phase changes (melting, boiling) use latent heat formulas instead.
- You can rearrange to solve for any variable: m = q/(cΔT), c = q/(mΔT), ΔT = q/(m c).
Example:
Heat 200 g of water (c = 4.18 J/g·°C) from 20 °C to 80 °C:
ΔT = 60 °C, so q = 200 × 4.18 × 60 = 50,160 J ≈ 50.2 kJ.
q = m · c · ΔT
- q = heat energy gained or lost (joules, J)
- m = mass of the substance (kg or g)
- c = specific heat capacity (J/(kg·K) or J/(g·°C))
- ΔT = change in temperature = T_final − T_initial (K or °C)
Notes:
- ΔT in K and °C are numerically the same, so either unit works as long as c’s units match m.
- q is positive when the substance absorbs heat (temperature rises) and negative when it releases heat.
- This equation applies only while the substance stays in the same phase. For phase changes (melting, boiling) use latent heat formulas instead.
- You can rearrange to solve for any variable: m = q/(cΔT), c = q/(mΔT), ΔT = q/(m c).
Example:
Heat 200 g of water (c = 4.18 J/g·°C) from 20 °C to 80 °C:
ΔT = 60 °C, so q = 200 × 4.18 × 60 = 50,160 J ≈ 50.2 kJ.
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