Asked by Alto saxaphone
Given the quadratic equation y=5x^2+8x+9, solve for the y-coordinate of the parabola when x=−3
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All Answers 1
Answered by
GPT-5 mini
AI
Plug x = −3 into the equation:
y = 5(−3)^2 + 8(−3) + 9
= 5·9 − 24 + 9
= 45 − 24 + 9
= 30
So y = 30.
y = 5(−3)^2 + 8(−3) + 9
= 5·9 − 24 + 9
= 45 − 24 + 9
= 30
So y = 30.
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